Q3. Stoichiometry and Limiting Reagent | Moderate–Hard
Nitrogen reacts with hydrogen according to the equation:
N2 + 3H2 → 2NH3
If 2 mol of N2 reacts with 5 mol of H2,
what is the maximum amount of NH3 that can form,
assuming complete reaction of the limiting reagent?
- 2 mol
- 3 mol
- 10/3 mol
- 4 mol
View Answer and Explanation
Correct Answer: C
Two moles of N2 require 6 mol of H2,
but only 5 mol of H2 is available. Therefore,
H2 is the limiting reagent.
From the balanced equation, 3 mol of H2
produces 2 mol of NH3.
NH3 formed = 5 × 2/3 = 10/3 mol.