Work, Energy and Power – Physics MCQs - 14 Mar 2026
Practice Work, Energy and Power MCQs based on NCERT Class 11 Physics.
These questions are useful for NEET, JEE Main and MHT-CET exams and cover
concepts like work done, kinetic energy, potential energy and power.
Q1. Work done by a force is zero when:
- A. Force and displacement are parallel
- B. Force and displacement are perpendicular
- C. Force is maximum
- D. Displacement is maximum
Q2. The kinetic energy of a body of mass 2 kg moving with velocity 5 m/s is:
- A. 10 J
- B. 20 J
- C. 25 J
- D. 50 J
Q3. The SI unit of power is:
- A. Joule
- B. Watt
- C. Newton
- D. Pascal
Q4. Potential energy of a body increases when:
- A. Height increases
- B. Velocity increases
- C. Mass decreases
- D. Time increases
Q5. Power is defined as:
- A. Work × time
- B. Work / time
- C. Force × time
- D. Energy × time
Answer Key
| Question |
Correct Answer |
| Q1 |
B |
| Q2 |
C |
| Q3 |
B |
| Q4 |
A |
| Q5 |
B |
Detailed Explanations
Q1 Explanation:
Work done is given by W = F s cosθ.
If force and displacement are perpendicular (θ = 90°), cos90° = 0,
so work done becomes zero.
Q2 Explanation:
Kinetic energy is calculated using the formula:
Substituting values:
KE = ½ × 2 × (5²) = 25 J.
Q3 Explanation:
The SI unit of power is Watt (W).
1 Watt = 1 Joule/second.
Q4 Explanation:
Gravitational potential energy depends on height.
Potential energy = mgh.
When height increases, potential energy increases.
Q5 Explanation:
Power is defined as the rate of doing work.
Laws of Motion – Physics MCQs - 13 Mar 2026
Practice Laws of Motion MCQs based on NCERT Class 11 Physics.
These questions are useful for NEET, JEE Main and MHT-CET exams
and cover concepts like Newton’s laws, force, inertia, and friction.
Q1. Newton’s First Law of Motion is also known as:
- A. Law of acceleration
- B. Law of inertia
- C. Law of momentum
- D. Law of gravitation
Q2. The SI unit of force is:
- A. Joule
- B. Watt
- C. Newton
- D. Pascal
Q3. A force of 20 N acts on a body of mass 5 kg. The acceleration produced is:
- A. 2 m/s²
- B. 4 m/s²
- C. 5 m/s²
- D. 10 m/s²
Q4. According to Newton’s Third Law of Motion, action and reaction:
- A. Act on the same body
- B. Act on different bodies
- C. Are unequal in magnitude
- D. Act in the same direction
Q5. The frictional force between two surfaces depends on:
- A. Area of contact only
- B. Nature of surfaces in contact
- C. Speed of motion
- D. Volume of the object
Answer Key
| Question |
Correct Answer |
| Q1 |
B |
| Q2 |
C |
| Q3 |
B |
| Q4 |
B |
| Q5 |
B |
Detailed Explanations
Q1 Explanation:
Newton’s First Law states that a body remains at rest or in uniform motion
unless acted upon by an external force. This property is called inertia.
Q2 Explanation:
The SI unit of force is Newton (N).
1 Newton is the force required to produce an acceleration of 1 m/s² in a body of mass 1 kg.
Q3 Explanation:
Using Newton’s Second Law:
F = ma
a = F / m = 20 / 5 = 4 m/s².
Q4 Explanation:
Newton’s Third Law states that for every action there is an equal and opposite reaction.
These forces act on different bodies.
Q5 Explanation:
The frictional force depends on the nature of the surfaces in contact
and the normal reaction between them.
Motion in a Plane – Physics MCQs - 12 Mar 2026
Practice Motion in a Plane MCQs based on NCERT Class 11 Physics.
These concept-based questions are useful for NEET, JEE Main and MHT-CET exams.
Topics include vectors, projectile motion and circular motion basics.
Q1. Which of the following quantities is a vector quantity?
- A. Speed
- B. Distance
- C. Velocity
- D. Time
Q2. The angle between two equal vectors for their resultant to be equal to either vector is:
- A. 30°
- B. 60°
- C. 90°
- D. 120°
Q3. The horizontal range of a projectile is maximum when the angle of projection is:
- A. 30°
- B. 45°
- C. 60°
- D. 90°
Q4. A body moving in a circle with constant speed experiences:
- A. Zero acceleration
- B. Constant acceleration
- C. Centripetal acceleration
- D. No force
Q5. The SI unit of angular velocity is:
- A. rad/s
- B. m/s
- C. rad
- D. m
Answer Key
| Question |
Correct Answer |
| Q1 |
C |
| Q2 |
D |
| Q3 |
B |
| Q4 |
C |
| Q5 |
A |
Detailed Explanations
Q1 Explanation:
Velocity has both magnitude and direction, therefore it is a vector quantity.
Q2 Explanation:
For two vectors of equal magnitude A:
R = √(A² + A² + 2A² cosθ).
If R = A, solving gives θ = 120°.
Q3 Explanation:
Range of projectile:
R = (u² sin2θ) / g.
Range is maximum when sin2θ = 1 → θ = 45°.
Q4 Explanation:
In circular motion the direction of velocity changes continuously,
therefore the body experiences centripetal acceleration.
Q5 Explanation:
Angular velocity is the rate of change of angular displacement.
The SI unit is radian per second (rad/s).
NEET Physics MCQs – Motion in a Straight Line (NCERT Based) 11 Mar 2026
Practice important Motion in a Straight Line MCQs based on NCERT Class 11 Physics.
These concept-based questions are useful for NEET, JEE Main and MHT-CET exams.
The questions focus on displacement, velocity, acceleration and equations of motion.
Q1. If the velocity of a particle changes from 10 m/s to 30 m/s in 5 seconds, the acceleration of the particle is:
- A. 2 m/s²
- B. 4 m/s²
- C. 6 m/s²
- D. 8 m/s²
Q2. A body starts from rest and moves with uniform acceleration of 2 m/s². The distance travelled in 5 seconds is:
- A. 10 m
- B. 20 m
- C. 25 m
- D. 50 m
Q3. The area under a velocity–time graph represents:
- A. Acceleration
- B. Displacement
- C. Velocity
- D. Force
Q4. A car moving with velocity 20 m/s comes to rest in 4 seconds. The retardation is:
- A. 2 m/s²
- B. 3 m/s²
- C. 4 m/s²
- D. 5 m/s²
Q5. Which of the following statements is correct for uniform motion?
- A. Acceleration is constant but non-zero
- B. Velocity remains constant
- C. Speed changes with time
- D. Displacement is zero
Answer Key
| Question |
Correct Answer |
| Q1 |
B |
| Q2 |
C |
| Q3 |
B |
| Q4 |
D |
| Q5 |
B |
Detailed Explanations
Q1 Explanation:
Acceleration = (v − u) / t
= (30 − 10) / 5 = 20 / 5 = 4 m/s².
Q2 Explanation:
Using equation of motion:
s = ut + ½at²
u = 0, a = 2, t = 5
s = 0 + ½ × 2 × 25 = 25 m.
Q3 Explanation:
The area under a velocity-time graph gives the total displacement covered during that time interval.
Q4 Explanation:
a = (v − u) / t
= (0 − 20) / 4 = −5 m/s².
Magnitude of retardation = 5 m/s².
Q5 Explanation:
In uniform motion, velocity remains constant and acceleration is zero.
NEET Physics MCQs – Units and Measurements (NCERT Based) - 10 Mar 2026
Practice important Units and Measurements MCQs based on NCERT concepts useful for
NEET, JEE Main and MHT-CET exams. These questions help strengthen concepts of SI units,
dimensions, and error analysis.
Q1. Which of the following is not a fundamental SI unit?
- A. Kelvin
- B. Mole
- C. Newton
- D. Candela
Q2. The dimensional formula of velocity is:
- A. [M⁰ L¹ T⁻¹]
- B. [M¹ L⁰ T⁻¹]
- C. [M⁰ L¹ T⁻²]
- D. [M¹ L¹ T⁻²]
Q3. If the percentage error in measurement of length and breadth of a rectangle are 2% and 3%, the percentage error in area will be:
Q4. Which of the following physical quantities is dimensionless?
- A. Strain
- B. Velocity
- C. Momentum
- D. Force
Q5. The dimensional formula of force is:
- A. [M L T⁻¹]
- B. [M L² T⁻²]
- C. [M L T⁻²]
- D. [M⁰ L T⁻²]
Answer Key
| Question |
Correct Answer |
| Q1 |
C |
| Q2 |
A |
| Q3 |
B |
| Q4 |
A |
| Q5 |
C |
Detailed Explanations
Q1 Explanation:
Fundamental SI units include meter, kilogram, second, ampere, kelvin, mole, and candela.
Newton is a derived unit used to measure force.
Q2 Explanation:
Velocity = displacement / time.
Therefore dimensional formula = [L T⁻¹] or [M⁰ L¹ T⁻¹].
Q3 Explanation:
For multiplication operations, percentage errors are added.
Area = length × breadth.
Total percentage error = 2% + 3% = 5%.
Q4 Explanation:
Strain is defined as change in length divided by original length.
Since it is a ratio of two lengths, it has no dimensions.
Q5 Explanation:
From Newton’s Second Law: Force = mass × acceleration.
Acceleration has dimensions [L T⁻²].
Therefore dimensional formula of force = [M L T⁻²].